3n^2+5n-418=0

Solution for 3n^2+5n-418=0 equation:

3n^2+5n-418=0

a = 3; b = 5; c = -418;
Δ = b2-4ac
Δ = 52-4·3·(-418)
Δ = 5041
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5041}=71$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-71}{2*3}=\frac{-76}{6}
=-12+2/3
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+71}{2*3}=\frac{66}{6}
=11
$